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Fungrim entry: e1e106

π=limn16nn(2nn)2\pi = \lim_{n \to \infty} \frac{{16}^{n}}{n {{2 n \choose n}}^{2}}
\pi = \lim_{n \to \infty} \frac{{16}^{n}}{n {{2 n \choose n}}^{2}}
Fungrim symbol Notation Short description
Piπ\pi The constant pi (3.14...)
SequenceLimitlimnaf(n)\lim_{n \to a} f(n) Limiting value of sequence
Powab{a}^{b} Power
Binomial(nk){n \choose k} Binomial coefficient
Infinity\infty Positive infinity
Source code for this entry:
    Formula(Equal(Pi, SequenceLimit(Div(Pow(16, n), Mul(n, Pow(Binomial(Mul(2, n), n), 2))), For(n, Infinity)))))

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2021-03-15 19:12:00.328586 UTC