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Fungrim entry: 4e5947

atan(z)=k=0(1)kz2k+12k+1\operatorname{atan}(z) = \sum_{k=0}^{\infty} \frac{{\left(-1\right)}^{k} {z}^{2 k + 1}}{2 k + 1}
Assumptions:zC  and  z<1z \in \mathbb{C} \;\mathbin{\operatorname{and}}\; \left|z\right| < 1
\operatorname{atan}(z) = \sum_{k=0}^{\infty} \frac{{\left(-1\right)}^{k} {z}^{2 k + 1}}{2 k + 1}

z \in \mathbb{C} \;\mathbin{\operatorname{and}}\; \left|z\right| < 1
Fungrim symbol Notation Short description
Atanatan(z)\operatorname{atan}(z) Inverse tangent
Sumnf(n)\sum_{n} f(n) Sum
Powab{a}^{b} Power
Infinity\infty Positive infinity
CCC\mathbb{C} Complex numbers
Absz\left|z\right| Absolute value
Source code for this entry:
    Formula(Equal(Atan(z), Sum(Div(Mul(Pow(-1, k), Pow(z, Add(Mul(2, k), 1))), Add(Mul(2, k), 1)), For(k, 0, Infinity)))),
    Assumptions(And(Element(z, CC), Less(Abs(z), 1))))

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2021-03-15 19:12:00.328586 UTC