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Fungrim entry: 338055

π=8n=01(4n+1)(4n+3)\pi = 8 \sum_{n=0}^{\infty} \frac{1}{\left(4 n + 1\right) \left(4 n + 3\right)}
\pi = 8 \sum_{n=0}^{\infty} \frac{1}{\left(4 n + 1\right) \left(4 n + 3\right)}
Fungrim symbol Notation Short description
Piπ\pi The constant pi (3.14...)
Sumnf(n)\sum_{n} f(n) Sum
Infinity\infty Positive infinity
Source code for this entry:
    Formula(Equal(Pi, Mul(8, Sum(Div(1, Mul(Add(Mul(4, n), 1), Add(Mul(4, n), 3))), For(n, 0, Infinity))))))

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2021-03-15 19:12:00.328586 UTC