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Fungrim entry: 209fc8

(zk+1)=zkk+1(zk){z \choose k + 1} = \frac{z - k}{k + 1} {z \choose k}
Assumptions:zC  and  kZ0z \in \mathbb{C} \;\mathbin{\operatorname{and}}\; k \in \mathbb{Z}_{\ge 0}
{z \choose k + 1} = \frac{z - k}{k + 1} {z \choose k}

z \in \mathbb{C} \;\mathbin{\operatorname{and}}\; k \in \mathbb{Z}_{\ge 0}
Fungrim symbol Notation Short description
Binomial(nk){n \choose k} Binomial coefficient
CCC\mathbb{C} Complex numbers
ZZGreaterEqualZn\mathbb{Z}_{\ge n} Integers greater than or equal to n
Source code for this entry:
    Formula(Equal(Binomial(z, Add(k, 1)), Mul(Div(Sub(z, k), Add(k, 1)), Binomial(z, k)))),
    Variables(z, k),
    Assumptions(And(Element(z, CC), Element(k, ZZGreaterEqual(0)))))

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2021-03-15 19:12:00.328586 UTC