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Fungrim entry: 1fa6b7

ez+2nπi=ez{e}^{z + 2 n \pi i} = {e}^{z}
Assumptions:zCandnZz \in \mathbb{C} \,\mathbin{\operatorname{and}}\, n \in \mathbb{Z}
{e}^{z + 2 n \pi i} = {e}^{z}

z \in \mathbb{C} \,\mathbin{\operatorname{and}}\, n \in \mathbb{Z}
Fungrim symbol Notation Short description
Expez{e}^{z} Exponential function
ConstPiπ\pi The constant pi (3.14...)
ConstIii Imaginary unit
CCC\mathbb{C} Complex numbers
ZZZ\mathbb{Z} Integers
Source code for this entry:
    Formula(Equal(Exp(Add(z, Mul(Mul(Mul(2, n), ConstPi), ConstI))), Exp(z))),
    Variables(z, n),
    Assumptions(And(Element(z, CC), Element(n, ZZ))))

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Copyright (C) Fredrik Johansson and contributors. Fungrim is provided under the MIT license. The source code is on GitHub.

2019-10-05 13:11:19.856591 UTC